Sound Insulation of Building Partitions Rw - Guide to PN-B-02151-3 Standard
17 stycznia 2026 | Architecture
Noise in residential buildings is one of the most common problems reported by residents. According to research by the Central Statistical Office, over 40% of Poles living in multi-family buildings complain about disturbing noise from neighbors. The key parameter determining a partition's ability to attenuate sounds is the weighted sound reduction index Rw.
Properly designed building partitions can effectively protect against noise, ensuring acoustic comfort for residents. If you want to quickly check the sound insulation of your partition, use our acoustic insulation calculator Rw.
What is Sound Insulation Rw?
The weighted sound reduction index Rw is a single-number parameter that defines a building partition's ability to attenuate airborne sounds. It is expressed in decibels [dB] and represents a simplified characteristic of the acoustic properties of a partition across the entire frequency range audible to humans (100-3150 Hz).
The interpretation is simple: the higher the Rw value, the better the sound insulation. A wall with Rw = 55 dB attenuates sounds much more effectively than a wall with Rw = 40 dB. In practice, a difference of 10 dB means that the sound is perceived as half as loud.
The decibel scale is logarithmic, which means:
- A difference of 3 dB is a barely noticeable change in loudness
- A difference of 10 dB is a subjectively twofold change in loudness
- A difference of 20 dB is a fourfold change in loudness
It is worth distinguishing the assessment stages:
- Rw - weighted sound reduction index, determined in laboratory for the partition alone
- RA,1 = Rw + C - index with the spectrum adaptation term C
- RA,1,R = RA,1 − 2 dB - design value with a margin when laboratory data are used
- R'A,1 ≈ RA,1,R − Ka - approximate in-building assessment including flanking transmission Ka
C is part of the partition's acoustic declaration, while Ka depends on flanking partitions and junctions. Therefore, catalogue Rw is not the result obtained in a completed building; flanking transmission must also be considered for partitions between dwellings.
Legal Basis - Standard PN-B-02151-3:2015
In Poland, requirements for sound insulation of partitions in residential buildings are defined by standard PN-B-02151-3:2015 "Building acoustics. Protection against noise in buildings. Part 3: Requirements for sound insulation of partitions in buildings and building elements".
This standard is referenced in the Regulation of the Minister of Infrastructure on technical conditions to be met by buildings and their location, which gives it mandatory status for all new residential buildings.
Standard Requirements for Building Partitions
Standard PN-B-02151-3:2015 specifies minimum values of the sound reduction index R'A,1 for various types of partitions in multi-family residential buildings:
| Partition Type | Required R'A,1 |
|---|---|
| 1.1 Floor between apartments | R'A,1 ≥ 51 dB |
| 1.2 Wall between apartments | R'A,1 ≥ 50 dB |
| 1.3 Wall to corridor/staircase - no door | R'A,1 ≥ 50 dB |
| 1.3 Wall with door (with anteroom) | R'A,1 ≥ 30 dB |
| 1.3 Wall with door (without anteroom) | R'A,1 ≥ 38 dB |
| 1.3 Entrance door (with anteroom) | RA,1,R ≥ 30 dB |
| 1.3 Entrance door (without anteroom) | RA,1,R ≥ 35 dB |
| 1.4 Partition apartment-garage/technical room | R'A,1 ≥ 58 dB |
| 1.5 Partition apartment-music venue | R'A,1 ≥ 65 dB |
| 1.6 Floor apartment-office (mixed-use building) | R'A,1 ≥ 55 dB |
| 1.7 Wall room-bathroom / between rooms | RA,1,R ≥ 35 dB |
| 1.7 Floor in multi-level apartment | RA,1,R ≥ 45 dB |
| II Wall between buildings (semi-detached/terraced) | R'A,1 ≥ 52 dB |
The required laboratory Rw depends on C, the 2 dB design margin and, for partitions between dwellings, the selected Ka scenario.
Mass Law - Basic Principle of Building Acoustics
The fundamental principle governing the sound insulation of single-layer partitions is the so-called mass law. According to it, the sound insulation of a partition increases with its surface mass.
Approximate empirical formula for single-layer partitions:
Where:
- m' - surface mass of the partition in kg/m²
Several practical conclusions follow from the mass law:
- Doubling the mass increases this estimator by approximately 11 dB
- Heavy materials (concrete, solid brick) naturally have better insulation than light ones (aerated concrete, plasterboard)
- Increasing wall thickness from the same material proportionally increases its mass and insulation
Calculation Example:
A solid brick wall 25 cm thick has a surface mass m' = 425 kg/m².
Rw ≈ 37.5 · log₁₀(425) − 42 = 37.5 · 2.628 − 42 ≈ 56.6 dB
In practice, for 25 cm solid brick, the catalog value of Rw is approximately 52 dB, which confirms the correctness of the mass law as an approximation.
Calculating Insulation of Single-Layer Walls
For single-layer partitions, sound insulation depends mainly on:
- Surface mass - according to the mass law
- Material stiffness - too stiff materials have worse properties at certain frequencies
- Airtightness - any leak drastically reduces insulation
In design practice, Rw values provided by material manufacturers or from sound insulation catalogs are most commonly used. Example values for typical materials:
| Material and Thickness | Mass [kg/m²] | Rw [dB] |
|---|---|---|
| Solid ceramic brick 12 cm | 204 | 42 |
| Solid ceramic brick 25 cm | 425 | 52 |
| Silicate brick 18 cm | 324 | 49 |
| Silicate brick 24 cm | 432 | 52 |
| Aerated concrete 24 cm | 144 | 44 |
| Aerated concrete 36 cm | 216 | 48 |
| Reinforced concrete 18 cm | 432 | 50 |
| Reinforced concrete 25 cm | 600 | 56 |
All the above values can be quickly checked and compared in our acoustic insulation calculator, which contains an extensive database of building materials.
Double and Lightweight Walls — Selecting a System
The calculator's estimator applies only to massive double walls with a cavity. It is a preliminary assessment: mechanical ties and junction workmanship can significantly reduce the result. For lightweight walls, choose complete tested systems with declared Rw(C), not a sum of individual boards and mineral wool.
Composite Partitions - Windows and Doors in Walls
One of the most common design problems is calculating the insulation of a partition containing elements with different insulation values - e.g., walls with windows or doors.
The insulation of a composite partition is calculated using the formula:
Where:
- Si - area of the i-th element in m²
- Rwi - insulation of the i-th element in dB
- Stotal - total area of the partition in m²
This formula shows that the weakest element determines the insulation of the entire partition. Even a small area with low insulation drastically reduces the overall result.
Example: Wall with doors
Wall between apartment and corridor: 8 m² of wall (Rw = 52 dB) + 2 m² of door (Rw = 27 dB).
Calculation:
- Transmission through wall: 8 · 10^(-52/10) = 8 · 0.0000063 = 0.0000504
- Transmission through door: 2 · 10^(-27/10) = 2 · 0.002 = 0.004
- Sum: 0.0040504
- Rw,composite = -10 · log₁₀(0.0040504/10) = -10 · log₁₀(0.000405) = 34 dB
Although the wall itself has Rw = 52 dB, a door with Rw = 27 dB reduces the Rw of the entire partition to only 34 dB. With typical C = −1 dB, a 2 dB design margin and Ka = 2, R'A,1 is about 29 dB, so the partition does not meet R'A,1 ≥ 38 dB for a wall with a door and no anteroom (item 1.3 of the standard).
Solution: A door with Rw = 35 dB raises the partition's Rw to about 41.7 dB, but the final R'A,1 is only about 36.7 dB. With these assumptions, a door with Rw of about 37 dB is needed (partition Rw about 43.5 dB and R'A,1 about 38.5 dB), along with proper sealing.
This type of calculation can be quickly performed in our acoustic insulation calculator in "Composite partition" mode.
System Linings and Mineral Wool
Mineral wool is part of a lining or lightweight-wall system; it does not have a stand-alone ΔRw gain. ΔRw applies to the full board + frame + wool system and depends on the base wall — the better the base, the smaller the improvement usually is. Do not use EPS bonded directly to a wall as an acoustic solution: resonance can worsen insulation.
Plasterboard Walls - Lightweight Acoustic Solutions
Plasterboard walls on steel frame construction with mineral wool filling can achieve very high sound insulation with relatively low mass:
| Construction | Thickness | Rw [dB] |
|---|---|---|
| Single plasterboard 12.5 mm | 1.25 cm | 28 |
| Double plasterboard 2x12.5 mm | 2.5 cm | 34 |
| Single plasterboard wall with 5 cm wool | 7.5 cm | 42-45 |
| Double plasterboard wall with 5 cm wool | 10 cm | 48-52 |
| Double plasterboard wall with 10 cm wool | 15 cm | 55-58 |
Key principles for plasterboard walls:
- Use double cladding - significantly increases insulation
- Fill gaps with mineral wool - without it, insulation drops by 8-12 dB
- Avoid acoustic bridges - steel profiles should not connect both claddings
- Seal edges - any gap is a path for sound
Common Design and Execution Errors
Error 1: Acoustic bridges
Every rigid connection between layers of a double wall dramatically reduces its insulation. Typical bridges include:
- Wall ties connecting layers
- Common lintels above openings
- Pipes and installation channels passing through the partition
- Electrical outlets "opposite" in two apartments
Error 2: Leaks
A gap 1 mm wide and 1 m long can reduce the insulation of a wall with Rw = 50 dB to only 35 dB. Typical leak locations:
- Joints with floor and ceiling
- Window and door frames
- Installation penetrations
- Plaster cracks
Error 3: Too light materials
Popular aerated concrete blocks (e.g., 24 cm, Rw ≈ 44 dB) often do not meet requirements for walls between apartments. After C, the design margin and Ka are included, the required Rw is higher than the R'A,1 requirement itself; check it in the calculator for the selected scenario.
Error 4: Ignoring doors and windows in calculations
As shown earlier, even a small door area with low insulation can dominate the insulation of the entire partition. The partition should always be checked as a whole.
Practical Design Tips
-
For walls between apartments (R'A,1 ≥ 50 dB):
- With typical C = −1 dB and Ka = 2, a wall with Rw = 52 dB gives R'A,1 ≈ 47 dB and does not meet the requirement; Rw of about 55 dB is needed
- Choose a heavy partition or a complete tested lightweight system
- Check airtightness and limit acoustic bridges
-
For walls to corridor/staircase without door (R'A,1 ≥ 50 dB):
- High insulation required due to staircase noise
- Reinforced concrete 20 cm or solid brick 25 cm
- Consider additional insulation layer
-
For entrance doors (RA,1,R ≥ 30 dB with anteroom / ≥ 35 dB without):
- With typical C = −1 dB, standard solid doors (Rw = 26-28 dB) do not comply even with the less strict requirement
- With typical C = −1 dB, an entrance door without anteroom needs laboratory Rw of about 38 dB to achieve RA,1,R ≥ 35 dB
- Pay attention to seals and threshold
-
For floors (R'A,1 ≥ 51 dB for airborne sounds):
- Reinforced concrete 18-20 cm as minimum
- Floating floor for impact sound insulation
Summary
Sound insulation of building partitions is a key parameter affecting resident comfort. Polish standard PN-B-02151-3:2015 specifies minimum requirements that partitions in new residential buildings must meet.
Key principles:
- Mass matters - heavier partitions insulate better
- Double walls with wool-filled gap achieve the best parameters
- The weakest element determines the insulation of the entire partition
- Airtightness is equally important as mass
- Convert Rw through C, the design margin and — for partitions between dwellings — Ka
If you want to quickly check the sound insulation of a designed partition, use our acoustic insulation calculator Rw. The program will calculate the Rw index based on the selected structural material and optional insulation, then verify compliance with Polish regulations.
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